Bug report #7600

$geometry parameter does not expand to layer geometry column name

Added by Jeremy Palmer almost 7 years ago. Updated 11 months ago.

Status:Closed
Priority:Normal
Assignee:-
Category:Web Services clients/WFS
Affected QGIS version:master Regression?:No
Operating System:ALL Easy fix?:No
Pull Request or Patch supplied:No Resolution:end of life
Crashes QGIS or corrupts data:No Copied to github as #:16530

Description

Within the QGIS Expression Builder the $geometry parameter does not expand to layer geometry column name when using WFS. The QGIS Expression to OGC filter always use 'geometry' as the name.

example with layer geometry column "is the_geom"

QGIS Expression: "intersects($geometry, geomFromWKT('POINT (5 6)'))"

OGC XML:

<ogc:Filter>
<ogc:Intersects>
<ogc:PropertyName>*geometry*</ogc:PropertyName>
<gml:Point><gml:coordinates cs=\\",\\" ts=\\" \\">5.0,6.0</gml:coordinates></gml:Point>
</ogc:Intersects>
</ogc:Filter>

History

#1 Updated by Jürgen Fischer over 5 years ago

  • Target version changed from Version 2.0.0 to Future Release - Lower Priority

#2 Updated by Even Rouault about 4 years ago

The issue seems to be resolved in master

I used the following layer :
http://demo.opengeo.org/geoserver/wfs?SERVICE=WFS&VERSION=1.0.0&REQUEST=GetFeature&TYPENAME=ne:ne_10m_admin_0_countries&SRSNAME=EPSG:4326

and expression :
intersects($geometry, geomFromWKT('POINT (2 49)'))

and it selected France as expected.

The geometry name of this layer is the_geom

#3 Updated by Even Rouault about 4 years ago

Update: my above comment only applies after adding a WFS layer and using an expression in the table

The issue still exists when adding a filter to a not yet loaded layer.

#4 Updated by Giovanni Manghi over 2 years ago

  • Regression? set to No
  • Easy fix? set to No

#5 Updated by Giovanni Manghi 11 months ago

  • Resolution set to end of life
  • Status changed from Open to Closed

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