Bug report #14939
Cannot use virtual field for styling if it uses values from another virtual field
| Status: | Closed | ||
|---|---|---|---|
| Priority: | Normal | ||
| Assignee: | - | ||
| Category: | Virtual Fields | ||
| Affected QGIS version: | 2.14.3 | Regression?: | No |
| Operating System: | Easy fix?: | No | |
| Pull Request or Patch supplied: | No | Resolution: | |
| Crashes QGIS or corrupts data: | No | Copied to github as #: | 22890 |
Description
If you create a virtual field "v_field_1" in a shapefile which contains values, you can style the layer using this field such as Categorized or Graduated style.
But if you create another virtual field "v_field_2" which takes values from "v_field_1" (e.g. using a simple expression like: "v_field_1"), then "v_field_2" cannot be styled. When you go to either the Categorized or Graduated style and select "v_field_2", it is blank.
I am using QGIS 2.14.3-Essen for Windows 7 64-bit.
Associated revisions
Fix virtual fields which depend on other virtual fields may not be
calculated in some circumstances (fix #14939)
Fix virtual fields which depend on other virtual fields may not be
calculated in some circumstances (fix #14939)
(cherry-picked from df0d5969aa8e3bf0ec653bb6d6395afe1cf58950)
History
#1
Updated by Joseph Liam about 8 years ago
The values of "v_field_2" are correctly calculated in the attribute table but just don't show up when being styled.
#2
Updated by Nyall Dawson about 8 years ago
- Status changed from Open to Closed
Fixed in changeset df0d5969aa8e3bf0ec653bb6d6395afe1cf58950.