Bug report #1339
Can't set projection to WGS84 UTM Zone 15N
Status: | Closed | ||
---|---|---|---|
Priority: | Low | ||
Assignee: | nobody - | ||
Category: | Projection Support | ||
Affected QGIS version: | Regression?: | No | |
Operating System: | Gentoo | Easy fix?: | No |
Pull Request or Patch supplied: | Resolution: | invalid | |
Crashes QGIS or corrupts data: | Copied to github as #: | 11399 |
Description
Hello there,
I'm trying to write a python plugin which needs to determine georeferencing info for layers.
I set a layer's projection by right clicking the layer, selecting properties and then selecting Change SRS under the general tab.
I select SRSID 2992 ( UTM Z 15N ) and click apply
In my python code, I am doing something like this:
srsID = regionLayer.srs().srsid()
srsID always comes out as 3344 instead of 2992!
Other queries through srs() also seem to say the layer is of longlat instead of UTM as I tried to define.
Is this a known issue?
Regards,
Vince
History
#1 Updated by Fernando Pacheco - about 16 years ago
On Linux (Ubuntu) and Windows:
I loaded a layer with custom projection (South America LCC: +proj=lcc +lat_1=-5 +lat_2=-42 +lat_0=-32 +lon_0=-60 +x_0=0 +y_0=0 +ellps=aust_SA +units=m no_defs) from a PostgreSQL/PostGIS database. Then I selected the layer with the mouse. I opened the Python console and wrote iface.activeLayer().srs().srsid(). I get the following result 1001.
I loaded a layer with UTM WGS84 15N from a Shape File. Then I selected the layer with the mouse. I opened the Python console and wrote iface.activeLayer().srs().srid(). I get the following result 2992.
I set a layer's projection by right clicking the layer, selecting properties and then selecting Change SRS under the general tab. I changed the SRC several times in the same layer and ask again with iface.activeLayer().srs().srsid() and the result always change, then I believe that in my case it worked smoothly.
Could you please send me more information?. Regards, Fernando.
#2 Updated by vedgewater - about 16 years ago
Hi Fernando,
Sorry for not getting back to you sooner, I have been away last week.
Using python console, I am now able to reproduce the error....
If you:
1 Open the attached shape file in QGIS (it's lat/lon)
2 Save the this as a QGIS workspace
3 Right click the layer, properties, General tab, change SRS, select ID 2992
4 Hit Apply, then OK
5 save the workspace
6 Close QGIS
7 Open QGIS
8 Open last used workspace
9 Check through properties again, it should show the layer as UTM
10 Open python console:
11 iface.activeLayer().srs().srsid()
i get 2992
12 Close and re-open QGIS
13 Open the project again and type the following into python console:
def getVectorLayerByName(myName):
mc = iface.getMapCanvas()
nLayers = mc.layerCount()
for l in range(nLayers):
layer = mc.getZpos(l)
if str(layer.name()) == str(myName):
vlayer = QgsVectorLayer(str(layer.source()), str(myName), str(layer.getDataProvider().name()))
if vlayer.isValid():
return vlayer
regionLayer = getVectorLayerByName("boundaryPolygons_004")
regionLayer.srs().srsid()
i get 3344
now type iface.activeLayer().srs().srsid()
i get 2992
I think this might be something to do with changing the SRS in properties only being saved in the workspace and not in the layer itself. If I then save the shape file as a different layer...
(right click layer, save as...)
Add the layer and then in the console:
regionLayer = getVectorLayerByName("boundaryPolygons_005")
regionLayer.srs().srsid()
2992
iface.activeLayer().srs().srsid()
2992
Then it's working consistently.
Please bear with me as I'm new to QGIS!
Hopefully you can re-produce this now at your end. Please let me know if for some reason you can't see the layer I attached.
Regards,
Vince
#3 Updated by vedgewater - about 16 years ago
Hello again,
I've just realised that the code above has been strangely formatted, it's meant to read like
def getVectorLayerByName(myName): mc = iface.getMapCanvas() nLayers = mc.layerCount() for l in range(nLayers): layer = mc.getZpos(l) if str(layer.name()) == str(myName): vlayer = [[QgsVectorLayer]](str(layer.source()), str(myName), str(layer.getDataProvider().name())) if vlayer.isValid(): return vlayer regionLayer = getVectorLayerByName("boundaryPolygons_004") regionLayer.srs().srsid()
Regards,
Vince
#4 Updated by Fernando Pacheco - about 16 years ago
Vince,
If you just want to get the layer by name and then take for example the srsid believe that this code would be sufficient:
def getVectorLayerByName(myName): mc = iface.getMapCanvas() nLayers = mc.layerCount() for l in range(nLayers): layer = mc.getZpos(l) if str(layer.name()) == str(myName): return layer regionLayer = getVectorLayerByName("boundaryPolygons_004") regionLayer.srs().srsid()
Please, try it and tell me the results. Regards, Fernando.
#5 Updated by vedgewater - about 16 years ago
Hi Fernando,
Thanks for your help, I can use the code you posted without needing to use the "save layer as" workaround in my previous post. It's returning the correct SRS now.
I guess returning vlayer in my original code was the problem.
I shall update my code now...
Shall I make as resolved (fixed) ?
Regards,
Vince
#6 Updated by Fernando Pacheco - about 16 years ago
- Status changed from Open to Closed
- Resolution set to invalid
Is not a bug. Close.
#7 Updated by Anonymous over 15 years ago
Milestone Version 1.0.0 deleted