DualEdgeTriangulation.h.diff

Thomas Arnold, 2012-03-30 01:49 PM

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141 141
    unsigned int insertEdge( int dual, int next, int point, bool mbreak, bool forced );
142 142
    /**inserts a forced segment between the points with the numbers p1 and p2 into the triangulation and returns the number of a HalfEdge belonging to this forced edge or -100 in case of failure*/
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    int insertForcedSegment( int p1, int p2, bool breakline );
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    /**Threshold for the leftOfTest to handle numerical instabilities*/
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    //const static double leftOfTresh=0.00001;
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    const static double leftOfTresh;
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    /**Security to prevent endless loops in 'baseEdgeOfTriangle'. It there are more iteration then this number, the point will not be inserted*/
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    const static int nBaseOfRuns = 300000;
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    /**Returns the number of an edge which points to the point with number 'point' or -1 if there is an error*/
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    int baseEdgeOfPoint( int point );
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    /**returns the number of a HalfEdge from a triangle in which 'point' is in. If the number -10 is returned, this means, that 'point' is outside the convex hull. If -5 is returned, then numerical problems with the leftOfTest occured (and the value of the possible edge is stored in the variable 'mUnstableEdge'. -20 means, that the inserted point is exactly on an edge (the number is stored in the variable 'mEdgeWithPoint'). -25 means, that the point is already in the triangulation (the number of the point is stored in the member 'mTwiceInsPoint'. If -100 is returned, this means that something else went wrong*/
151 152