QUuid cannot be constructed from string in Qt6

qgis · Jul 20, 2021 · ea43f6b · ea43f6b
1 parent 87e2653
commit ea43f6b
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Showing 2 changed files with 2 additions and 2 deletions.
diff --git a/src/gui/attributetable/qgsattributetableview.cpp b/src/gui/attributetable/qgsattributetableview.cpp
@@ -456,7 +456,7 @@ void QgsAttributeTableView::actionTriggered()
 
   if ( action->data().toString() == QLatin1String( "user_action" ) )
   {
-    mFilterModel->layer()->actions()->doAction( action->property( "action_id" ).toString(), f );
+    mFilterModel->layer()->actions()->doAction( action->property( "action_id" ).toUuid(), f );
   }
   else if ( action->data().toString() == QLatin1String( "map_layer_action" ) )
   {

diff --git a/src/gui/attributetable/qgsdualview.cpp b/src/gui/attributetable/qgsdualview.cpp
@@ -897,7 +897,7 @@ void QgsDualView::viewWillShowContextMenu( QMenu *menu, const QModelIndex &maste
   }
 
   menu->addSeparator();
-  QgsAttributeTableAction *a = new QgsAttributeTableAction( tr( "Open Form" ), this, QString(), rowSourceIndex );
+  QgsAttributeTableAction *a = new QgsAttributeTableAction( tr( "Open Form" ), this, QUuid(), rowSourceIndex );
   menu->addAction( tr( "Open Form…" ), a, &QgsAttributeTableAction::featureForm );
 }