Don't restrict smooth algorithm outputs for use as inputs to line

parameters Fixes #45503
qgis · Oct 14, 2021 · 59de78a · 59de78a
1 parent 515747d
commit 59de78a
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diff --git a/src/analysis/processing/qgsalgorithmsmooth.cpp b/src/analysis/processing/qgsalgorithmsmooth.cpp
@@ -49,11 +49,6 @@ QString QgsSmoothAlgorithm::outputName() const
   return QObject::tr( "Smoothed" );
 }
 
-QgsProcessing::SourceType QgsSmoothAlgorithm::outputLayerType() const
-{
-  return QgsProcessing::TypeVectorLine;
-}
-
 QString QgsSmoothAlgorithm::shortHelpString() const
 {
   return QObject::tr( "This algorithm smooths the geometries in a line or polygon layer. It creates a new layer with the "

diff --git a/src/analysis/processing/qgsalgorithmsmooth.h b/src/analysis/processing/qgsalgorithmsmooth.h
@@ -46,7 +46,6 @@ class QgsSmoothAlgorithm : public QgsProcessingFeatureBasedAlgorithm
 
   protected:
     QString outputName() const override;
-    QgsProcessing::SourceType outputLayerType() const override;
     bool prepareAlgorithm( const QVariantMap &parameters, QgsProcessingContext &context, QgsProcessingFeedback *feedback ) override;
     QgsFeatureList processFeature( const QgsFeature &feature,  QgsProcessingContext &context, QgsProcessingFeedback *feedback ) override;
     QgsProcessingFeatureSource::Flag sourceFlags() const override;